(y^2-4y-21)/(5y^2-25y-120)

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Solution for (y^2-4y-21)/(5y^2-25y-120) equation:


D( y )

5*y^2-(25*y)-120 = 0

5*y^2-(25*y)-120 = 0

5*y^2-(25*y)-120 = 0

5*y^2-25*y-120 = 0

5*y^2-25*y-120 = 0

DELTA = (-25)^2-(-120*4*5)

DELTA = 3025

DELTA > 0

y = (3025^(1/2)+25)/(2*5) or y = (25-3025^(1/2))/(2*5)

y = 8 or y = -3

y in (-oo:-3) U (-3:8) U (8:+oo)

(y^2-(4*y)-21)/(5*y^2-(25*y)-120) = 0

(y^2-4*y-21)/(5*y^2-25*y-120) = 0

y^2-4*y-21 = 0

y^2-4*y-21 = 0

DELTA = (-4)^2-(-21*1*4)

DELTA = 100

DELTA > 0

y = (100^(1/2)+4)/(1*2) or y = (4-100^(1/2))/(1*2)

y = 7 or y = -3

(y+3)*(y-7) = 0

5*y^2-25*y-120 = 0

5*(y^2-5*y-24) = 0

y^2-5*y-24 = 0

DELTA = (-5)^2-(-24*1*4)

DELTA = 121

DELTA > 0

y = (121^(1/2)+5)/(1*2) or y = (5-121^(1/2))/(1*2)

y = 8 or y = -3

5*(y+3)*(y-8) = 0

((y+3)*(y-7))/(5*(y+3)*(y-8)) = 0

( y+3 )

y+3 = 0 // - 3

y = -3

( y-7 )

y-7 = 0 // + 7

y = 7

y in { -3}

y = 7

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